Subtopic: 12D process F0 calculation for Clostridium botulinum
Question Statement:
In thermal sterilization of low-acid canned food, the decimal reduction time of *Clostridium botulinum* spores at $121.1^\circ\text{C}$ is $D_{121.1} = 0.35\text{ min}$. The minimum thermal lethality time ($F_0$) required to achieve a commercial $12D$ sterility reduction is ________ $\text{min}$ (round off to two decimal places).
Answer Key:
4.20
Step-by-Step Solution & Explanation
The $12D$ concept requires reducing the microbial spore population by $12$ decimal cycles ($12$ log reductions):
$F_0 = 12 \times D_{121.1}$
Given $D_{121.1} = 0.35\text{ min}$:
$F_0 = 12 \times 0.35 = 4.20\text{ min}$