Question Bank • QB_EXP_DFE_REF_001 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Refrigeration Cycles, Refrigerants & Cold Storage Design

Subtopic: Refrigeration COP from enthalpy states

Question Statement:

A cold storage vapor compression refrigeration system operates with refrigerant R-134a. The specific enthalpies at key cycle states are: evaporator outlet $h_1 = 390.0\text{ kJ/kg}$, compressor outlet $h_2 = 425.0\text{ kJ/kg}$, and condenser outlet (before throttling) $h_3 = h_4 = 240.0\text{ kJ/kg}$. The Coefficient of Performance ($COP$) of the cycle is ________ (round off to two decimal places).

Answer Key:

4.29

Step-by-Step Solution & Explanation

The refrigerating effect ($RE$) is: $RE = h_1 - h_4 = 390.0 - 240.0 = 150.0\text{ kJ/kg}$ The work of compression ($W$) is: $W = h_2 - h_1 = 425.0 - 390.0 = 35.0\text{ kJ/kg}$ The Coefficient of Performance is: $COP = \frac{RE}{W} = \frac{150.0}{35.0} = 4.29$
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