Question Bank • QB_EXP_EM_002 MSQ • 2 Marks

Section 1: Engineering Mathematics

Calculus

Subtopic: Homogeneous function – Euler's theorem on homogeneous functions

Question Statement:

Let $u(x, y) = \sin^{-1}\left(\frac{x^3 + y^3}{x + y}\right)$. According to Euler's theorem on homogeneous functions, which of the following relations are CORRECT?

Options:

  • (A) $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} = 2 \tan u$
  • (B) The degree of homogeneity of the argument $z = \sin u = \frac{x^3 + y^3}{x + y}$ is 2
  • (C) $x^2 \frac{\partial^2 u}{\partial x^2} + 2xy \frac{\partial^2 u}{\partial x \partial y} + y^2 \frac{\partial^2 u}{\partial y^2} = 2 \tan u (2 \sec^2 u - 1)$
  • (D) $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} = 2 \sin u$

Answer Key:

A, B, C

Step-by-Step Solution & Explanation

1. Let $z = \sin u = \frac{x^3 + y^3}{x + y}$. 2. For $z$, substituting $(tx, ty)$ gives $\frac{t^3(x^3 + y^3)}{t(x+y)} = t^2 z$. Hence $z$ is a homogeneous function of degree $n = 2$. (Statement B is True) 3. By Euler's theorem for homogeneous functions of a dependent function: $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} = n \frac{f(u)}{f'(u)} = 2 \frac{\sin u}{\cos u} = 2 \tan u$ Hence Statement A is True and D is False. 4. Second order derivative extension of Euler's theorem: $x^2 \frac{\partial^2 u}{\partial x^2} + 2xy \frac{\partial^2 u}{\partial x \partial y} + y^2 \frac{\partial^2 u}{\partial y^2} = G(u)[G'(u) - 1]$ where $G(u) = 2 \tan u$. Here $G'(u) = 2 \sec^2 u$. Therefore: $2 \tan u [2 \sec^2 u - 1]$. (Statement C is True)
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