Let $A$ be a $2 \times 2$ matrix satisfying $A^2 - 16A + I = 0$, where $I$ is the identity matrix. If $\lambda$ is an eigenvalue of $A$, the value of $\lambda^2 + \lambda^{-2}$ is ________ (answer in integer).
Answer Key:
254
Step-by-Step Solution & Explanation
Since $\lambda$ is an eigenvalue of $A$, it satisfies the characteristic equation:
$\lambda^2 - 16\lambda + 1 = 0$
Dividing through by $\lambda$ (since $\lambda \neq 0$):
$\lambda + \frac{1}{\lambda} = 16$
Squaring both sides:
$\left(\lambda + \frac{1}{\lambda}\right)^2 = 16^2 = 256$
$\lambda^2 + 2 + \frac{1}{\lambda^2} = 256 \implies \lambda^2 + \lambda^{-2} = 256 - 2 = 254$