Question Bank • QB_EXP_EM_EIG_029 NAT • 2 Marks

Section 1: Engineering Mathematics

Linear Algebra: Eigenvalues & Cayley-Hamilton

Subtopic: Cayley–Hamilton theorem

Question Statement:

Let $A$ be a $2 \times 2$ matrix satisfying $A^2 - 31A + I = 0$, where $I$ is the identity matrix. If $\lambda$ is an eigenvalue of $A$, the value of $\lambda^2 + \lambda^{-2}$ is ________ (answer in integer).

Answer Key:

959

Step-by-Step Solution & Explanation

Since $\lambda$ is an eigenvalue of $A$, it satisfies the characteristic equation: $\lambda^2 - 31\lambda + 1 = 0$ Dividing through by $\lambda$ (since $\lambda \neq 0$): $\lambda + \frac{1}{\lambda} = 31$ Squaring both sides: $\left(\lambda + \frac{1}{\lambda}\right)^2 = 31^2 = 961$ $\lambda^2 + 2 + \frac{1}{\lambda^2} = 961 \implies \lambda^2 + \lambda^{-2} = 961 - 2 = 959$
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