Question Bank • QB_EXP_EM_PD_014 NAT • 2 Marks

Section 1: Engineering Mathematics

Calculus: Partial Derivatives & Maxima-Minima

Subtopic: Constrained extrema and Lagrange multipliers

Question Statement:

The minimum value of the function $f(x, y) = x^2 + y^2 - 30x - 34y$ on $\mathbb{R}^2$ is equal to ________ (answer in integer).

Answer Key:

-514

Step-by-Step Solution & Explanation

Completing the square for $x$ and $y$: $f(x, y) = (x^2 - 30x + 225) + (y^2 - 34y + 289) - (225 + 289)$ $f(x, y) = (x - 15)^2 + (y - 17)^2 - (514)$ Since $(x - 15)^2 \ge 0$ and $(y - 17)^2 \ge 0$, the minimum occurs at $(x, y) = (15, 17)$: $f_{\min} = -(514) = -514$
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