Question Bank • QB_EXP_FM_GEN_031 MCQ • 1 Mark

Section 2: Farm Machinery

Combine Harvesters: Threshing & Separation Mechanisms

Subtopic: Rasp bar, spike tooth and axial flow cylinders

Question Statement:

A tractor implement has a working width of $2.5\text{ m}$ and operates at a forward speed of $5.5\text{ km/h}$. The theoretical field capacity (TFC) of the machine is:

Options:

  • (A) $1.38\text{ ha/h}$
  • (B) $1.66\text{ ha/h}$
  • (C) $1.10\text{ ha/h}$
  • (D) $2.07\text{ ha/h}$

Answer Key:

A

Step-by-Step Solution & Explanation

Theoretical field capacity (TFC) in ha/h is given by: $\text{TFC} = \frac{W \times S}{10}$ Where $W = 2.5\text{ m}$ and $S = 5.5\text{ km/h}$: $\text{TFC} = \frac{2.5 \times 5.5}{10} = 1.38\text{ ha/h}$
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