Question Bank • QB_EXP_FP_CYC_008 NAT • 2 Marks

Section 3: Farm Power

Sources of Power

Subtopic: Thermodynamic cycles of IC engines

Question Statement:

In the Diesel cycle P-v diagram, the compression ratio is $16.0$ and the cut-off ratio is $2.0$. Taking the adiabatic exponent $\gamma = 1.4$, determine the expansion ratio $r_e = V_4/V_3$ during process $3 \to 4$ (round off to one decimal place).

Answer Key:

8

Step-by-Step Solution & Explanation

Compression ratio $r = \frac{V_1}{V_2} = 16$. Cut-off ratio $r_c = \frac{V_3}{V_2} = 2$. Since $V_4 = V_1$, the expansion ratio is: $r_e = \frac{V_4}{V_3} = \frac{V_1}{V_3} = \frac{V_1/V_2}{V_3/V_2} = \frac{r}{r_c} = \frac{16}{2} = 8.0$.
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