Question Bank • QB_EXP_FP_CYC_044 NAT • 2 Marks

Section 3: Farm Power

Sources of Power

Subtopic: Thermodynamic cycles of IC engines

Question Statement:

A 4-stroke Diesel engine operating on the cycle shown in the diagram produces an indicated power of $40\text{ kW}$ at $2000\text{ rpm}$. Calculate the indicated work done per cycle per cylinder in Joules, assuming a single cylinder engine (round off to the nearest integer).

Answer Key:

2400

Step-by-Step Solution & Explanation

For a 4-stroke engine, power strokes per minute $n = N/2 = 2000/2 = 1000\text{ cycles/min} = \frac{1000}{60}\text{ cycles/sec}$. $W = \frac{IP}{n} = \frac{40000}{1000/60} = \frac{40000 \times 60}{1000} = 2400\text{ J/cycle}$.
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