Subtopic: Diesel and petrol properties (calorific value, density, flash point)
Question Statement:
A tractor diesel engine delivers a brake power of $38.0\text{ kW}$ while consuming $8.0\text{ kg/h}$ of fuel. The Brake Specific Fuel Consumption (BSFC) of the engine is:
Options:
(A) $210.5\text{ g/kWh}$
(B) $263.1\text{ g/kWh}$
(C) $168.4\text{ g/kWh}$
(D) $315.8\text{ g/kWh}$
Answer Key:
A
Step-by-Step Solution & Explanation
BSFC is defined as fuel mass consumption per unit of brake power delivered per hour:
$\text{BSFC} = \frac{\dot{m}_f}{\text{BP}} = \frac{8.0\text{ kg/h} \times 1000\text{ g/kg}}{38.0\text{ kW}} = \frac{8000}{38.0} = 210.5\text{ g/kWh}$