Subtopic: Diesel and petrol properties (calorific value, density, flash point)
Question Statement:
A tractor diesel engine delivers a brake power of $36.0\text{ kW}$ while consuming $6.5\text{ kg/h}$ of fuel. The Brake Specific Fuel Consumption (BSFC) of the engine is:
Options:
(A) $180.6\text{ g/kWh}$
(B) $225.8\text{ g/kWh}$
(C) $144.5\text{ g/kWh}$
(D) $270.9\text{ g/kWh}$
Answer Key:
A
Step-by-Step Solution & Explanation
BSFC is defined as fuel mass consumption per unit of brake power delivered per hour:
$\text{BSFC} = \frac{\dot{m}_f}{\text{BP}} = \frac{6.5\text{ kg/h} \times 1000\text{ g/kg}}{36.0\text{ kW}} = \frac{6500}{36.0} = 180.6\text{ g/kWh}$