Question Bank • QB_EXP_FP_PWR_002 NAT • 2 Marks

Section 3: Farm Power

Engine Power: Indicated, Brake & Friction Power

Subtopic: Mean effective pressure and indicated power

Question Statement:

A $4\text{-cylinder}$, four-stroke tractor diesel engine has a cylinder bore of $10\text{ cm}$ and a stroke of $12\text{ cm}$. When running at $2000\text{ rpm}$, the mean effective pressure is $600\text{ kPa}$. The indicated power developed by the engine is ________ $\text{kW}$ (round off to two decimal places, take $\pi = 3.1416$).

Answer Key:

37.70

Step-by-Step Solution & Explanation

For a multi-cylinder 4-stroke engine: $\text{IP} = \frac{n \cdot P_m \cdot L \cdot A \cdot N}{60 \times 2}$ Where: - $n = 4$ - $P_m = 600.0\text{ kPa} = 600.0\text{ kN/m}^2$ - $L = 0.12\text{ m}$ - $A = \frac{\pi \times 0.1^2}{4} = 0.007854\text{ m}^2$ - $N = 2000.0\text{ rpm}$ $\text{IP} = \frac{4 \times 600.0 \times 0.12 \times 0.007854 \times 2000.0}{120} = 37.70\text{ kW}$
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