Question Bank • QB_EXP_GA_PRB_001 NAT • 1 Mark

Section 8: General Aptitude

Quantitative: Permutations, Combinations & Probability

Subtopic: Combinations selection calculation

Question Statement:

A quality control panel must choose a committee of $3$ agronomists out of $8$ qualified candidates. The total number of distinct ways this committee can be formed is ________.

Answer Key:

56

Step-by-Step Solution & Explanation

The number of ways to choose $r$ items from $n$ items without regard to order is: $C(n, r) = \frac{n!}{r! (n - r)!} = \frac{8!}{3! 5!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56$
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