Question Bank • QB_EXP_IDE_CAN_002 NAT • 1 Mark

Section 5: Irrigation and Drainage Engineering

Canal Design: Lacey, Kennedy & Tractive Force

Subtopic: Lacey silt factor calculation

Question Statement:

The average particle diameter of bed material in an alluvial canal is $d = 0.36\text{ mm}$. Lacey's silt factor $f$ for this bed material is ________ (round off to two decimal places).

Answer Key:

1.06

Step-by-Step Solution & Explanation

Lacey's silt factor is given by: $f = 1.76 \sqrt{d_{mm}}$ For $d = 0.36\text{ mm}$: $f = 1.76 \times \sqrt{0.36} = 1.76 \times 0.60 = 1.056$ Rounding to two decimal places: $1.06$.
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