For an ideal pressure-compensating (PC) drip emitter, the emitter discharge exponent $x$ in the equation $q = k H^x$ is theoretically equal to:
Options:
(A) $0.0$
(B) $0.5$
(C) $1.0$
(D) $0.75$
Answer Key:
A
Step-by-Step Solution & Explanation
In a pressure-compensating emitter, an elastic diaphragm deflects under rising pressure to reduce flow cross-section, keeping discharge constant regardless of pressure variations. Hence $q \propto H^0 \implies x \approx 0.0$. For fully turbulent orifice emitters, $x = 0.5$; for laminar emitters, $x = 1.0$.