Question Bank • QB_EXP_SWCE_SEP_001 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Soil Permeability, Seepage & Flow Nets

Subtopic: Seepage discharge under weir from flow net

Question Statement:

A flow net constructed under a diversion weir consists of $4$ flow channels and $12$ equipotential drops. The total hydraulic head across the weir is $H = 5.0\text{ m}$ and the hydraulic conductivity of the foundation soil is $k = 2.5 \times 10^{-5}\text{ m/s}$. The seepage discharge per unit length of the weir is ________ $\text{m}^3/\text{day per m}$ (round off to two decimal places).

Answer Key:

3.60

Step-by-Step Solution & Explanation

From flow net theory, the seepage discharge per unit width is: $q = k H \frac{N_f}{N_d}$ Given $k = 2.5 \times 10^{-5}\text{ m/s}$, $H = 5.0\text{ m}$, $N_f = 4$, $N_d = 12$: $q = (2.5 \times 10^{-5}) \times 5.0 \times \frac{4}{12} = 4.166667e-05\text{ m}^3/\text{s per m}$ Converting to $\text{m}^3/\text{day}$ ($1\text{ day} = 86400\text{ s}$): $q = 4.166667e-05 \times 86400 = 3.600\text{ m}^3/\text{day per m}$ Rounding to two decimal places: $3.60\text{ m}^3/\text{day per m}$.
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