Subtopic: Measurement of force, stress, torque, speed, displacement and acceleration on machine elements – shafts, couplings, keys, bearings and knuckle joints
Question Statement:
A tractor PTO shaft rotates at $540\text{ rpm}$ and delivers $35\text{ kW}$ of mechanical power to an implement. The torque transmitted through the shaft in $\text{N}\cdot\text{m}$ is ________ (round off to 1 decimal place). Take $\pi = 3.1416$.
Answer Key:
618.9
Step-by-Step Solution & Explanation
The relationship connecting mechanical power $P$ and torque $T$ is:
$P = \frac{2 \pi N T}{60}$
$T = \frac{60 \times P}{2 \pi N} = \frac{60 \times (35 \times 10^3)}{2 \times 3.1416 \times 540} = \frac{2,100,000}{3392.9} \approx 618.94\text{ N}\cdot\text{m} \approx 618.9\text{ N}\cdot\text{m}$