Question Bank • QB_FM_046 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A 6-row planter has a total working width of $W = 4.5\text{ m}$ and travels at an operating speed of $S = 6.0\text{ km/h}$. In planting a $7.5\text{ ha}$ rectangular field, the net operating time spent planting along rows is $2.50\text{ h}$, while time lost in turning at headlands and refilling hoppers is $0.625\text{ h}$. The effective field capacity ($EFC$) of the planter in $\text{ha/h}$ is ________ (round off to 2 decimal places).

Answer Key:

2.40

Step-by-Step Solution & Explanation

1. Total operational time ($T$): $T = T_{\text{operating}} + T_{\text{lost}} = 2.50\text{ h} + 0.625\text{ h} = 3.125\text{ h}$ 2. Effective Field Capacity ($EFC$): $EFC = \frac{\text{Total Area}}{T} = \frac{7.5\text{ ha}}{3.125\text{ h}} = 2.40\text{ ha/h}$ (Note: Theoretical field capacity $TFC = \frac{4.5 \times 6.0}{10} = 2.70\text{ ha/h}$; Field efficiency $\eta_f = \frac{2.40}{2.70} \approx 88.9\%$).
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