Question Bank • QB_FM_054 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Equipment for precision agriculture

Question Statement:

In an impact-plate grain yield sensor mounted at the head of a combine clean-grain elevator, clean grain strikes an inclined impact plate at an approach velocity of $v_1 = 3.2\text{ m/s}$ and leaves with negligible normal rebound velocity. If the measured normal impact force on the load cell is $F_n = 48.0\text{ N}$, the instantaneous mass flow rate of grain $\dot{m}$ in $\text{kg/s}$ is ________ (answer in integer).

Answer Key:

15

Step-by-Step Solution & Explanation

From Newton's second law / impulse-momentum principle: $F_n = \dot{m} \cdot \Delta v_n = \dot{m} \cdot (v_1 - 0) = \dot{m} \cdot v_1$ $\dot{m} = \frac{F_n}{v_1} = \frac{48.0\text{ N}}{3.2\text{ m/s}} = 15.0\text{ kg/s}$
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