Question Bank • QB_FM_113 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Forces acting on a tillage tool

Question Statement:

A moldboard plow bottom cuts a furrow slice of width $35\text{ cm}$ and depth $18\text{ cm}$. The measured total horizontal draft is $3.402\text{ kN}$. Calculate the specific draft of the soil in $\text{N/cm}^2$.

Answer Key:

5.4

Step-by-Step Solution & Explanation

Furrow cross-sectional area: $A = w \times d = 35\text{ cm} \times 18\text{ cm} = 630\text{ cm}^2$ Draft $D = 3.402\text{ kN} = 3402\text{ N}$. Specific draft: $D_s = \frac{D}{A} = \frac{3402\text{ N}}{630\text{ cm}^2} = 5.40\text{ N/cm}^2$
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