Question Bank • QB_FM_114 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A 4-bottom tractor plow has a total cutting width of $1.4\text{ m}$. It operates at a forward speed of $5.0\text{ km/h}$. If the field efficiency is $80\%$, calculate the effective field capacity in $\text{ha/h}$.

Answer Key:

0.56

Step-by-Step Solution & Explanation

Theoretical field capacity: $TFC = \frac{W \times S}{10} = \frac{1.4 \times 5.0}{10} = 0.70\text{ ha/h}$ Effective field capacity: $EFC = TFC \times 0.80 = 0.70 \times 0.80 = 0.56\text{ ha/h}$
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