Question Bank • QB_FM_126 NAT • 2 Marks

Section 2: Farm Machinery

Machine Design

Subtopic: Design and selection of machine elements – gears, pulleys, chains and sprockets and belts

Question Statement:

A flat belt transmits power at a belt speed of $v = 15\text{ m/s}$. The tension on the tight side is $T_1 = 1200\text{ N}$ and on the slack side is $T_2 = 400\text{ N}$. Calculate the power transmitted in $\text{kW}$.

Answer Key:

12

Step-by-Step Solution & Explanation

Power transmitted: $P = (T_1 - T_2) \times v = (1200 - 400)\text{ N} \times 15\text{ m/s} = 800 \times 15 = 12000\text{ W} = 12.0\text{ kW}$
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