Question Bank • QB_FM_GATE_003 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A 4-bottom tractor-drawn mouldboard plow having a total width of cut of $1.4\text{ m}$ is operated at a forward speed of $5.4\text{ km/h}$. If the field efficiency of the plowing operation is $80\%$, the actual field capacity of the plow is ________ $\text{ha/h}$ (round off to 2 decimal places).

Answer Key:

0.6

Step-by-Step Solution & Explanation

Field Capacity Calculation: $TFC = \frac{W \times S}{10} = \frac{1.4 \times 5.4}{10} = 0.756\text{ ha/h}$ $EFC = TFC \times 0.80 = 0.756 \times 0.80 = 0.6048\text{ ha/h}$ Rounding to 2 decimal places: **0.60** $\text{ha/h}$.
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