Question Bank • QB_FP_031 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Engine components

Question Statement:

A 4-cylinder tractor diesel engine has a piston stroke length of $L = 120\text{ mm}$ and operates at rated speed of $N = 2200\text{ rpm}$. The mean piston speed of the engine in $\text{m/s}$ is ________ (round off to 1 decimal place).

Answer Key:

8.8

Step-by-Step Solution & Explanation

Mean piston speed ($v_m$) is given by: $v_m = \frac{2 L N}{60}$ Given $L = 120\text{ mm} = 0.120\text{ m}$ and $N = 2200\text{ rpm}$: $v_m = \frac{2 \times 0.120 \times 2200}{60} = \frac{528}{60} = 8.8\text{ m/s}$
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