Subtopic: Steering and hydraulic control systems used in tractors
Question Statement:
An agricultural tractor has a wheelbase of $L = 2.20\text{ m}$ and a rear wheel track width of $B = 1.50\text{ m}$. When turning with the inner rear wheel completely locked by its independent steering brake, assuming pivot rotation about the center of the inner rear tire, the turning radius from the pivot point to the outer front wheel ($R = \sqrt{L^2 + B^2}$) in $\text{m}$ is ________ (round off to 2 decimal places).
Answer Key:
2.66
Step-by-Step Solution & Explanation
With the inner rear wheel locked, the center of turn coincides with the inner wheel ground contact point:
$R = \sqrt{L^2 + B^2} = \sqrt{2.20^2 + 1.50^2} = \sqrt{4.84 + 2.25} = \sqrt{7.09} \approx 2.6627\text{ m} \approx 2.66\text{ m}$