Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses
Question Statement:
A single plate dry friction clutch has two active friction surfaces with inner radius $100\text{ mm}$ and outer radius $150\text{ mm}$. The clamping spring provides an axial thrust of $2.5\text{ kN}$. If the coefficient of friction is $0.35$ and uniform wear theory is assumed, calculate the torque transmitting capacity of the clutch in $\text{N}\cdot\text{m}$.
Answer Key:
218.75
Step-by-Step Solution & Explanation
Under uniform wear theory, the mean friction radius is:
$R_m = \frac{r_1 + r_2}{2} = \frac{0.15 + 0.10}{2} = 0.125\text{ m}$
Friction surfaces $n = 2$.
Total torque capacity:
$T = n \times \mu \times W \times R_m = 2 \times 0.35 \times 2500\text{ N} \times 0.125\text{ m} = 218.75\text{ N}\cdot\text{m}$