Question Bank • QB_FP_109 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Thermodynamic principles of I.C. engines

Question Statement:

A tractor of wheelbase $1.8\text{ m}$ has static wheel reactions of $8\text{ kN}$ on front wheels and $16\text{ kN}$ on rear wheels. Calculate the horizontal distance of the tractor center of gravity from the rear axle centerline in $\text{meters}$.

Answer Key:

0.6

Step-by-Step Solution & Explanation

Total weight $W = R_f + R_r = 8 + 16 = 24\text{ kN}$. Taking moments about the rear axle: $R_f \times L = W \times x_r$ $8 \times 1.8 = 24 \times x_r$ $x_r = \frac{8 \times 1.8}{24} = \frac{14.4}{24} = 0.60\text{ m}$
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