Question Bank • QB_FP_111 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: I.C. engine systems – fuel, cooling, lubrication, ignition, electrical, intake and exhaust

Question Statement:

A tractor hydraulic system has a gear pump delivering $36\text{ L/min}$ at a working relief pressure of $17.5\text{ MPa}$. Calculate the hydraulic power delivered by the pump in $\text{kW}$.

Answer Key:

10.5

Step-by-Step Solution & Explanation

Hydraulic power $P_h$: $P_h = \frac{p \times Q}{60}$ Where: - $p$ is in $\text{MPa}$ ($17.5\text{ MPa}$) - $Q$ is in $\text{L/min}$ ($36\text{ L/min}$) $P_h = \frac{17.5 \times 36}{60} = \frac{630}{60} = 10.5\text{ kW}$
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