Question Bank • QB_FP_113 NAT • 1 Mark

Section 3: Farm Power

Farm Power

Subtopic: Fuels and combustion

Question Statement:

A reference fuel blend for diesel knock rating contains $48\text{ mL}$ of Cetane (Hexadecane) and $12\text{ mL}$ of Heptamethylnonane ($HMN$). Since HMN has a cetane rating of 15, calculate the Cetane Number ($CN$) of the fuel blend according to standard ASTM formulation ($CN = \% \text{Cetane} + 0.15 \times \% HMN$).

Answer Key:

83

Step-by-Step Solution & Explanation

Total volume $= 48 + 12 = 60\text{ mL}$. Percentage of Cetane $= \frac{48}{60} \times 100 = 80\%$. Percentage of HMN $= \frac{12}{60} \times 100 = 20\%$. $CN = 80 + (0.15 \times 20) = 80 + 3.0 = 83.0$
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