Question Bank • QB_FP_117 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses

Question Statement:

A tractor operates on firm tilled soil where the coefficient of rolling resistance is $0.08$. If the total weight of the tractor is $22\text{ kN}$, calculate the power required in $\text{kW}$ solely to overcome rolling resistance at a forward travel speed of $7.2\text{ km/h}$.

Answer Key:

3.52

Step-by-Step Solution & Explanation

Rolling resistance force: $R = \mu_r \times W = 0.08 \times 22000\text{ N} = 1760\text{ N}$ Forward speed: $v = 7.2\text{ km/h} = \frac{7.2}{3.6} = 2.0\text{ m/s}$ Power required: $P = \frac{R \times v}{1000} = \frac{1760 \times 2.0}{1000} = 3.52\text{ kW}$
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