Subtopic: I.C. engine systems – fuel, cooling, lubrication, ignition, electrical, intake and exhaust
Question Statement:
A pressurized tractor cooling system operates with a radiator cap rated at a gauge pressure of $70\text{ kPa}$. If pure water normally boils at $100^\circ\text{C}$ at atmospheric pressure, and the boiling point increases by approximately $0.28^\circ\text{C}$ per $\text{kPa}$ of pressure increase, calculate the elevated boiling point of coolant in $^\circ\text{C}$.
Answer Key:
119.6
Step-by-Step Solution & Explanation
Pressure elevation $\Delta P = 70\text{ kPa}$.
Boiling point elevation:
$\Delta T = 70 \times 0.28 = 19.6^\circ\text{C}$
Elevated boiling point:
$T_b = 100 + 19.6 = 119.6^\circ\text{C}$