Question Bank • QB_FP_134 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses

Question Statement:

A tractor engine produces $40\text{ kW}$ brake power while consuming diesel at $10\text{ kg/h}$. Calculate the brake specific fuel consumption ($bsfc$) in $\text{g/(kW}\cdot\text{h)}$.

Answer Key:

250

Step-by-Step Solution & Explanation

Brake specific fuel consumption: $bsfc = \frac{\text{Fuel consumption (kg/h)} \times 1000}{\text{Brake power (kW)}} = \frac{10 \times 1000}{40} = 250\text{ g/(kW}\cdot\text{h)}$
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