Question Bank • QB_FP_135 NAT • 1 Mark

Section 3: Farm Power

Farm Power

Subtopic: I.C. engine systems – fuel, cooling, lubrication, ignition, electrical, intake and exhaust

Question Statement:

A pair of bullocks exerts an average draft of $80\text{ kgf}$ while pulling a plow at a walking speed of $3.6\text{ km/h}$. Calculate the power developed by the bullock pair in $\text{hp}$ (metric horsepower, $1\text{ hp} = 75\text{ kgf}\cdot\text{m/s}$).

Answer Key:

1.067

Step-by-Step Solution & Explanation

Draft $D = 80\text{ kgf}$. Speed $v = 3.6\text{ km/h} = 1.0\text{ m/s}$. Power in $\text{kgf}\cdot\text{m/s}$: $P = 80 \times 1.0 = 80\text{ kgf}\cdot\text{m/s}$ In metric hp: $P = \frac{80}{75} = 1.067\text{ hp}$
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