Question Bank • QB_FP_153 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Power efficiencies and measurement, engine performance curves

Question Statement:

A four-cylinder four-stroke diesel engine develops a brake power of $36.0\text{ kW}$ at full load. During a Morse test, the brake power outputs obtained by cutting off cylinders 1, 2, 3, and 4 in turn are $25.5\text{ kW}$, $25.0\text{ kW}$, $25.2\text{ kW}$, and $25.3\text{ kW}$ respectively. Calculate the mechanical efficiency of the engine as a percentage (round off to 1 decimal place).

Answer Key:

83.7

Step-by-Step Solution & Explanation

Indicated power of individual cylinders: $IP_1 = 36.0 - 25.5 = 10.5\text{ kW}$ $IP_2 = 36.0 - 25.0 = 11.0\text{ kW}$ $IP_3 = 36.0 - 25.2 = 10.8\text{ kW}$ $IP_4 = 36.0 - 25.3 = 10.7\text{ kW}$ Total IP: $IP = 10.5 + 11.0 + 10.8 + 10.7 = 43.0\text{ kW}$ Mechanical efficiency: $\eta_m = \frac{36.0}{43.0} \times 100 = 83.72\% \approx 83.7\%$ Acceptable range: $83.0 - 84.5\%$.
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