Question Bank • QB_FP_163 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses

Question Statement:

A tractor travels a distance of $45.0\text{ m}$ in $10\text{ revolutions}$ of its rear drive wheels under zero-slip (no-load) condition on concrete. When pulling a heavy subsoiler in a tilled field, the tractor advances only $36.0\text{ m}$ in the same $10\text{ revolutions}$ of the drive wheels. Calculate the wheel slip as a percentage.

Answer Key:

20

Step-by-Step Solution & Explanation

Wheel slip is defined as: $S = \frac{s_0 - s_1}{s_0} \times 100 = \frac{45.0 - 36.0}{45.0} \times 100 = \frac{9.0}{45.0} \times 100 = 20.0\%$ Acceptable range: $19.5 - 20.5\%$.
← Previous (QB_FP_162) Next (QB_FP_ADV_036) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test