Subtopic: Thermodynamic principles of I.C. engines
Question Statement:
A tractor has a wheel tread width (center-to-center distance between rear wheels) of $1.50\text{ m}$. The height of the center of gravity (CG) above ground level is $0.75\text{ m}$. Assuming symmetric lateral weight distribution, calculate the critical static sideways slope angle in degrees at which lateral overturn will occur.
Answer Key:
45
Step-by-Step Solution & Explanation
Lateral overturning occurs when the line of action of gravity through the CG passes outside the downhill tire contact point.
$\tan(\theta_{\text{crit}}) = \frac{T/2}{h_{cg}} = \frac{1.50 / 2}{0.75} = \frac{0.75}{0.75} = 1.0$
$\theta_{\text{crit}} = \arctan(1.0) = 45.0^\circ$