Question Bank • QB_FP_GATE_005 NAT • 2 Marks

Section 3: Farm Power

Tractors and Power Tillers

Subtopic: Traction theory

Question Statement:

In a no-load traction test, a tractor drive tire makes 20 revolutions in traveling $100\text{ m}$. When pulling a heavy subsoiler over the same $100\text{ m}$ distance, it makes 25 revolutions. The percentage wheel slip is ________ $\%$ (in integer).

Answer Key:

20

Step-by-Step Solution & Explanation

Wheel Slip: $S = \left(1 - \frac{N_0}{N_L}\right) \times 100 = \left(1 - \frac{20}{25}\right) \times 100 = 20\%$ Hence, the wheel slip is **20** $\%$.
← Previous (QB_FP_GATE_003) Next (QB_SUB_FP_TRC_002) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test