Question Bank • QB_GA_075 NAT • 1 Mark

Section 8: General Aptitude

Quantitative Aptitude

Subtopic: Ratios & Percentages

Question Statement:

The ratio of present ages of two brothers $A$ and $B$ is $4 : 5$. Five years hence, the ratio of their ages will become $5 : 6$. Calculate the present age of brother $A$ in $\text{years}$.

Answer Key:

20

Step-by-Step Solution & Explanation

Let present ages be $4x$ and $5x$. After 5 years: $\frac{4x + 5}{5x + 5} = \frac{5}{6}$ $6(4x + 5) = 5(5x + 5)$ $24x + 30 = 25x + 25$ $x = 5$ Present age of $A = 4x = 4(5) = 20\text{ years}$.
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