Question Bank • QB_GA_133 NAT • 2 Marks

Section 8: General Aptitude

Quantitative Aptitude

Subtopic: Ratios & Percentages

Question Statement:

A candidate scores $36\%$ in an examination and fails by $24\text{ marks}$. Another candidate scores $48\%$ and passes by $36\text{ marks}$. Calculate the total maximum marks of the examination.

Answer Key:

500

Step-by-Step Solution & Explanation

Difference in percentage $= 48\% - 36\% = 12\%$. Difference in marks $= 36 - (-24) = 60\text{ marks}$. Therefore: $12\% \text{ of total marks} = 60 \implies \text{Total marks} = \frac{60}{0.12} = 500$
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