Question Bank • QB_IDE_ADV_099 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Groundwater Hydrology

Subtopic: Groundwater movement; Darcy's Law

Question Statement:

A stratified horizontal aquifer consists of three distinct layers: - Layer 1: thickness $d_1 = 2.0\text{ m}$, hydraulic conductivity $K_1 = 4.0\text{ m/day}$ - Layer 2: thickness $d_2 = 3.0\text{ m}$, hydraulic conductivity $K_2 = 1.0\text{ m/day}$ - Layer 3: thickness $d_3 = 5.0\text{ m}$, hydraulic conductivity $K_3 = 8.0\text{ m/day}$ The equivalent horizontal hydraulic conductivity ($K_h$) for groundwater flow parallel to the bedding planes in meters per day ($\text{m/day}$) is ________ (round off to two decimal places).

Answer Key:

5.10

Step-by-Step Solution & Explanation

1. Total aquifer thickness: $D = d_1 + d_2 + d_3 = 2.0 + 3.0 + 5.0 = 10.0\text{ m}$ 2. Equivalent horizontal hydraulic conductivity ($K_h$ for parallel flow): $K_h = \frac{K_1 d_1 + K_2 d_2 + K_3 d_3}{D}$ 3. Substituting values: $K_1 d_1 = 4.0 \times 2.0 = 8.0\text{ m}^2/\text{day}$ $K_2 d_2 = 1.0 \times 3.0 = 3.0\text{ m}^2/\text{day}$ $K_3 d_3 = 8.0 \times 5.0 = 40.0\text{ m}^2/\text{day}$ $\sum K_i d_i = 8.0 + 3.0 + 40.0 = 51.0\text{ m}^2/\text{day}$ $K_h = \frac{51.0}{10.0} = 5.10\text{ m/day}$ (Notice $K_h$ is weighted heavily by the thick, permeable third layer).
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