Question Bank • QB_IDE_EXP_059 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Irrigation Water Conveyance and Application Methods

Subtopic: Surface, sprinkler and micro irrigation methods

Question Statement:

A pressure-compensating drip emitter has a discharge exponent of $x = 0.0$ in the flow equation $q = k h^x$. If the operating pressure head $h$ doubles from $10\text{ m}$ to $20\text{ m}$, calculate the ratio of the new discharge to the original discharge ($q_2 / q_1$).

Answer Key:

1

Step-by-Step Solution & Explanation

$\frac{q_2}{q_1} = \left(\frac{h_2}{h_1}\right)^x = \left(\frac{20}{10}\right)^0 = 2^0 = 1.0$
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