Question Bank • QB_IDE_EXP_075 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Irrigation Water Conveyance and Application Methods

Subtopic: Surface, sprinkler and micro irrigation methods

Question Statement:

A sprinkler nozzle of orifice area $a = 2.0 \times 10^{-4}\text{ m}^2$ operates under a pressure head of $h = 20\text{ m}$. If the coefficient of discharge is $C_d = 0.95$, calculate the nozzle discharge in $\text{L/s}$. (Take $g = 9.81\text{ m/s}^2$)

Answer Key:

3.76

Step-by-Step Solution & Explanation

Theoretical velocity: $v = \sqrt{2 g h} = \sqrt{2 \times 9.81 \times 20} = \sqrt{392.4} \approx 19.809\text{ m/s}$ Discharge: $Q = C_d \times a \times v = 0.95 \times (2.0 \times 10^{-4}) \times 19.809 = 0.003764\text{ m}^3/\text{s} = 3.764\text{ L/s}$
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