Question Bank • QB_IDE_EXP_076 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Wells and Pumps

Subtopic: Classification of pumps

Question Statement:

Calculate the specific speed ($N_s = \frac{N \sqrt{Q}}{H^{3/4}}$ in rpm, $\text{m}^3/\text{s}$, $\text{m}$) of a centrifugal pump operating at $N = 1450\text{ rpm}$, discharge $Q = 0.04\text{ m}^3/\text{s}$, and total head $H = 16\text{ m}$.

Answer Key:

36.25

Step-by-Step Solution & Explanation

$\sqrt{Q} = \sqrt{0.04} = 0.20$ $H^{3/4} = (16)^{3/4} = (16^{1/4})^3 = 2^3 = 8$ $N_s = \frac{1450 \times 0.20}{8} = \frac{290}{8} = 36.25$
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