Question Bank • QB_IDE_EXP_094 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Irrigation Water Conveyance and Application Methods

Subtopic: Surface, sprinkler and micro irrigation methods

Question Statement:

In a solid-set sprinkler system, sprinklers are spaced $12\text{ m}$ along the lateral and the laterals are spaced $18\text{ m}$ along the main line. Each sprinkler discharges $1.2\text{ m}^3/\text{h}$. Calculate the application precipitation rate in $\text{mm/h}$.

Answer Key:

5.56

Step-by-Step Solution & Explanation

Area covered per sprinkler: $A = S_l \times S_m = 12\text{ m} \times 18\text{ m} = 216\text{ m}^2$ Discharge $Q = 1.2\text{ m}^3/\text{h}$. Application rate: $I = \frac{Q}{A} = \frac{1.2\text{ m}^3/\text{h}}{216\text{ m}^2} = 0.005556\text{ m/h} = 5.56\text{ mm/h}$
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