Question Bank • QB_PARAMETRIC_FM_MB_019MCQ • 1 Mark
Section 2: Farm Machinery
Primary Tillage: Mouldboard Ploughs & Forces
Subtopic: Specific draft calculation
Question Statement:
A single-bottom mouldboard plough has a width of cut of $34\text{ cm}$ and operates at a depth of $13\text{ cm}$. If the specific soil draft is $0.8\text{ N/cm}^2$, the total draft required by the plough bottom is: (Variation QB_PARAMETRIC_FM_MB_019)
Options:
(A) $353.6\text{ N}$
(B) $424.3\text{ N}$
(C) $282.9\text{ N}$
(D) $530.4\text{ N}$
Answer Key:
A
Step-by-Step Solution & Explanation
The total draft $D$ is the product of cross-sectional area of the furrow slice and the unit draft (specific draft):
$\text{Cross-sectional Area } A = w \times d = 34\text{ cm} \times 13\text{ cm} = 442\text{ cm}^2$
$\text{Total Draft } D = A \times \text{Specific Draft} = 442\text{ cm}^2 \times 0.8\text{ N/cm}^2 = 353.6\text{ N}$
Hence, the correct draft is $353.6\text{ N}$.