Question Bank • QB_SUB_APE_0030 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Material Handling

Subtopic: Size separation by screening

Question Statement:

In a screening operation, feed contains 40% oversize material ($x_F = 0.40$). Overflow product contains 90% oversize ($x_D = 0.90$) and underflow contains 10% oversize ($x_B = 0.10$). The mass flow rate of overflow per 100 kg of feed (in kg) is:

Answer Key:

37.5

Step-by-Step Solution & Explanation

Overall and component mass balances: $F = D + B = 100$ $F x_F = D x_D + B x_B$ $100(0.40) = 0.90 D + 0.10(100 - D)$ $40 = 0.90 D + 10 - 0.10 D = 0.80 D + 10$ $0.80 D = 30 \implies D = \frac{30}{0.80} = 37.50\text{ kg}$
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