Question Bank • QB_SUB_DFE_MEB_005 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Heat and Mass Transfer

Subtopic: Material and energy balances in food processing systems

Question Statement:

A single-effect evaporator concentrates $1500\text{ kg/h}$ of fruit juice containing $10\%$ total solids to a final concentration of $50\%$ total solids. The rate of water evaporated (in kg/h) is:

Answer Key:

1200.0

Step-by-Step Solution & Explanation

Overall solids balance: $F \times x_F = P \times x_P$ $1500 \times 0.10 = P \times 0.50 \implies P = \frac{150.0}{0.50} = 300.0\text{ kg/h}$ Total mass balance: $F = P + W \implies W = F - P = 1500 - 300.0 = 1200.0\text{ kg/h}$
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