Question Bank • QB_SUB_DFE_REF_001 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Refrigeration and cold storage basics and applications

Question Statement:

A vapor compression refrigeration plant operating on R-134a extracts heat from an apple cold storage room at a rate of $70\text{ kW}$. If the power consumed by the compressor is $20\text{ kW}$, the Coefficient of Performance (COP) of the refrigeration system is:

Answer Key:

3.5

Step-by-Step Solution & Explanation

Coefficient of Performance: $\text{COP} = \frac{\text{Refrigeration Effect } (Q_e)}{\text{Work Input } (W_{\text{comp}})} = \frac{70}{20} = 3.50$
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