Question Bank • QB_SUB_FP_BRK_002 NAT • 2 Marks

Section 3: Farm Power

Tractors and Power Tillers

Subtopic: Tractor clutches and brakes

Question Statement:

A single plate dry clutch has inner radius $r_1 = 80\text{ mm}$ and outer radius $r_2 = 120\text{ mm}$. If the coefficient of friction is $\mu = 0.35$ and axial spring force is $W = 3000\text{ N}$, by uniform wear theory ($r_m = \frac{r_1 + r_2}{2}$), the torque transmitting capacity for two friction surfaces (in N.m) is:

Answer Key:

210.0

Step-by-Step Solution & Explanation

Mean radius: $r_m = \frac{80 + 120}{2} = 100\text{ mm} = 0.10\text{ m}$ Torque capacity with $n = 2$ surfaces: $T = n \mu W r_m = 2 \times 0.35 \times 3000 \times 0.10 = 210.0\text{ N}\cdot\text{m}$
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