Question Bank • QB_SWCE_ADV_101 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Soil Mechanics

Subtopic: Fundamental definitions and relationships

Question Statement:

A compacted soil sample has a void ratio of $e = 0.65$ and a specific gravity of soil solids $G_s = 2.68$. If the degree of saturation of the soil is $S_r = 75.0\%$, the gravimetric water content $w$ of the soil in percent ($\text{\%}$) is ________ (round off to two decimal places).

Answer Key:

18.19

Step-by-Step Solution & Explanation

**Method 1: Phase Relationship Equation** From basic volumetric-gravimetric phase relations: $S_r \cdot e = w \cdot G_s \implies w = \frac{S_r \cdot e}{G_s}$ Given: - $S_r = 0.75$ - $e = 0.65$ - $G_s = 2.68$ $w = \frac{0.75 \times 0.65}{2.68} = \frac{0.4875}{2.68} = 0.181903 = 18.19\%$ **Method 2: Volume-Mass Balance Basis** Assuming volume of solids $V_s = 1.0\text{ m}^3$: - Mass of solids $M_s = G_s \rho_w V_s = 2.68 \times 1000 = 2680\text{ kg}$ - Volume of voids $V_v = e V_s = 0.65\text{ m}^3$ - Volume of water $V_w = S_r V_v = 0.75 \times 0.65 = 0.4875\text{ m}^3$ - Mass of water $M_w = \rho_w V_w = 487.5\text{ kg}$ - Water content $w = \frac{M_w}{M_s} = \frac{487.5}{2680} = 0.1819 = 18.19\%$
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